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y=(1+y^2)
We move all terms to the left:
y-((1+y^2))=0
We calculate terms in parentheses: -((1+y^2)), so:We add all the numbers together, and all the variables
(1+y^2)
We get rid of parentheses
y^2+1
Back to the equation:
-(y^2+1)
y-(y^2+1)=0
We get rid of parentheses
-y^2+y-1=0
We add all the numbers together, and all the variables
-1y^2+y-1=0
a = -1; b = 1; c = -1;
Δ = b2-4ac
Δ = 12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation
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